4p^2=40p-64

Solution for 4p^2=40p-64 equation:

4p^2=40p-64

We move all terms to the left:

4p^2-(40p-64)=0

We get rid of parentheses

4p^2-40p+64=0

a = 4; b = -40; c = +64;
Δ = b2-4ac
Δ = -402-4·4·64
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-24}{2*4}=\frac{16}{8}
=2
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+24}{2*4}=\frac{64}{8}
=8
$